WASSCE Physics · Density and Pressure in Fluids

Density, pressure in liquids and atmospheric pressure

By the WASSCE Tutor team

Updated 10 November 2026 · 8 min read · Prepared against the WASSCE syllabus.

Why does a sharp knife cut better than a blunt one? Why are the walls of a dam thicker at the bottom? Why do your ears pop when a plane takes off? Pressure answers all three — and pressure in liquids and air is one of the most examined topics in WASSCE Physics.

Learning objectives

By the end of this lesson you should be able to:

  • define density and relative density and calculate them
  • define pressure and calculate pressure in solids and liquids
  • use p=hρgp = h\rho g and explain the properties of liquid pressure
  • explain atmospheric pressure, the mercury barometer and the manometer
  • state Pascal's principle and apply it to hydraulic machines

Density and relative density

Definition

Density is mass per unit volume: ρ=mV\rho = \dfrac{m}{V}, in kg m⁻³ (or g cm⁻³; 1 g cm⁻³ = 1000 kg m⁻³).

Relative density is the ratio of the density of a substance to the density of water (no unit):

RD=density of substancedensity of water=mass of substancemass of equal volume of water\text{RD} = \dfrac{\text{density of substance}}{\text{density of water}} = \dfrac{\text{mass of substance}}{\text{mass of equal volume of water}}
RD=density of substancedensity of water=mass of substancemass of equal volume of water\begin{aligned}\text{RD} &= \dfrac{\text{density of substance}}{\text{density of water}} \\ &= \dfrac{\text{mass of substance}}{\text{mass of equal volume of water}}\end{aligned}

Water has density 1000 kg m⁻³ (RD = 1). Mercury has RD 13.6, so its density is 13 600 kg m⁻³.

Pressure

Definition

Pressure is the force acting normally (perpendicularly) per unit area:

p=FAp = \dfrac{F}{A}

Its SI unit is the pascal (Pa): 1 Pa = 1 N m⁻².

The same force produces a larger pressure on a smaller area:

  • a sharp knife or a needle has a tiny area, so it cuts or pierces easily
  • tractors and lorries have wide tyres; camels have broad feet: large areas give low pressure, so they do not sink into soft ground
  • a woman in stiletto heels exerts more pressure on a floor than an elephant standing on its broad feet
Worked example

A block of weight 120 N measures 0.2 m × 0.3 m × 0.5 m. Find the greatest and least pressures it can exert on the floor.

  • Greatest pressure: smallest face, 0.2×0.3=0.060.2 \times 0.3 = 0.06 m². p=1200.06=2000p = \dfrac{120}{0.06} = 2000 Pa.
  • Least pressure: largest face, 0.3×0.5=0.150.3 \times 0.5 = 0.15 m². p=1200.15=800p = \dfrac{120}{0.15} = 800 Pa.

Pressure in liquids

A tall can of water with three holes at different depths; water spurts out furthest from the lowest hole, showing that pressure increases with depth

Figure 1. Pressure in a liquid increases with depth. WASSCE Tutor diagram.

The pressure at depth hh in a liquid of density ρ\rho is

p=hρgp = h\rho g

(plus atmospheric pressure acting on the surface, if the total pressure is wanted).

Properties of pressure in a liquid

  1. Pressure increases with depth.
  2. At a given depth, pressure acts equally in all directions.
  3. Pressure depends on depth and density only — not on the shape or cross-section of the container.
  4. A liquid finds its own level: the surface is at the same height in connected vessels.
Worked example

Find the pressure due to water at the bottom of a well 12 m deep. If atmospheric pressure is 1.0×1051.0 \times 10^{5} Pa, find the total pressure there. (ρ=1000\rho = 1000 kg m⁻³, g=10g = 10 m s⁻²)

p=hρg=12×1000×10=1.2×105 Pap = h\rho g = 12 \times 1000 \times 10 = 1.2 \times 10^{5}\ \text{Pa}
p=hρg=12×1000×10=1.2×105 Pa\begin{aligned}p &= h\rho g \\ &= 12 \times 1000 \times 10 \\ &= 1.2 \times 10^{5}\ \text{Pa}\end{aligned}

Total =1.2×105+1.0×105=2.2×105= 1.2 \times 10^{5} + 1.0 \times 10^{5} = 2.2 \times 10^{5} Pa.

In Sierra Leone

Dams such as Bumbuna are built much thicker at the base because the water pressure on the wall increases with depth. Divers in the Atlantic off the Freetown peninsula feel the pressure on their ears increase rapidly as they go down: every 10 m of sea water adds about one atmosphere.

Atmospheric pressure

The air above us has weight, so it exerts a pressure: atmospheric pressure, about 1.01×1051.01 \times 10^{5} Pa at sea level (often called 1 atmosphere, or 760 mmHg). It decreases with altitude.

Evidence: the collapsing-can experiment (a can with a little water is boiled, sealed and cooled — it is crushed by atmospheric pressure as the steam condenses); drinking through a straw; a rubber sucker sticking to a wall.

The mercury barometer

A long glass tube of mercury inverted in a dish of mercury; the column stands about 760 millimetres high with a vacuum above it, supported by air pressure on the dish

Figure 2. A simple mercury barometer. WASSCE Tutor diagram.

Atmospheric pressure on the mercury in the dish supports the column. At sea level the column is about 760 mm high:

patm=hρg=0.76×13 600×9.8≈1.01×105 Pap_{atm} = h\rho g = 0.76 \times 13\,600 \times 9.8 \approx 1.01 \times 10^{5}\ \text{Pa}
patm=hρg=0.76×13 600×9.8≈1.01×105 Pa\begin{aligned}p_{atm} &= h\rho g \\ &= 0.76 \times 13\,600 \times 9.8 \\ &\approx 1.01 \times 10^{5}\ \text{Pa}\end{aligned}

Tilting the tube does not change the vertical height of the column. Water is not used because the column would need to be about 10.3 m tall.

The manometer

A U-tube manometer measures the pressure of a gas supply. One arm is connected to the gas; the other is open to the air. The difference in liquid levels hh gives the excess pressure of the gas above atmospheric: Δp=hρg\Delta p = h\rho g.

Pascal's principle and hydraulic machines

Definition

Pascal's principle: pressure applied to an enclosed fluid is transmitted equally to every part of the fluid and to the walls of the container.

In a hydraulic press, a small force on a small piston produces a large force on a large piston: F1A1=F2A2\dfrac{F_1}{A_1} = \dfrac{F_2}{A_2}. Applications: hydraulic jacks, hydraulic car brakes, barber's chairs, hydraulic lifts in garages.

Key points

  • Density ρ=m/V\rho = m/V; relative density compares with water (no unit).
  • Pressure p=F/Ap = F/A (Pa); smaller area → greater pressure.
  • Liquid pressure p=hρgp = h\rho g: increases with depth, same in all directions, independent of the container's shape.
  • Atmospheric pressure ≈ 1.01×1051.01 \times 10^{5} Pa ≈ 760 mmHg; measured with a barometer.
  • Pascal's principle underlies hydraulic machines.

WASSCE examination focus

WAEC tests this

Calculations with p=F/Ap = F/A and p=hρgp = h\rho g appear every year, often with atmospheric pressure added. You may be asked to describe the simple mercury barometer, explain why mercury and not water is used, state Pascal's principle and explain a hydraulic press or brake. Give units at every step.

Quick check

  1. Why do tractors have wide tyres?
  2. Find the pressure at a depth of 5 m in water (ρ=1000\rho = 1000 kg m⁻³, g=10g = 10 m s⁻²).
  3. State one reason why mercury is used in barometers.

Answers: 1. To spread the weight over a large area, reducing the pressure so they do not sink into soft soil. 2. 5×1000×10=5.0×1045 \times 1000 \times 10 = 5.0 \times 10^{4} Pa. 3. For example: its high density gives a short, convenient column (about 0.76 m instead of about 10 m for water).

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