WASSCE Physics · Circular Motion

Uniform circular motion and centripetal force

By the WASSCE Tutor team

Updated 10 November 2026 · 7 min read · Prepared against the WASSCE syllabus.

A body moving in a circle at steady speed is accelerating, even though its speed never changes. That surprising fact explains why you slide across the seat when a vehicle turns, how a spin dryer works and what holds the Moon in its orbit.

Learning objectives

By the end of this lesson you should be able to:

  • define angular displacement, angular velocity, period and frequency
  • relate linear speed to angular velocity, v=ωrv = \omega r
  • explain why a body in uniform circular motion is accelerating
  • calculate centripetal acceleration and centripetal force

Describing circular motion

Definition

Uniform circular motion is motion in a circle at constant speed.

QuantitySymbolMeaningUnit
Angular displacementθangle turned throughradian (rad)
Angular velocityωrate of change of angle, ω=θt\omega = \dfrac{\theta}{t}rad s⁻¹
PeriodTTtime for one complete revolutions
Frequencyffrevolutions per second, f=1Tf = \dfrac{1}{T}Hz

One complete revolution is 2π2\pi radians (360°), so

ω=2πT=2πf\omega = \dfrac{2\pi}{T} = 2\pi f
Definition

One radian is the angle subtended at the centre of a circle by an arc equal in length to the radius. 2π rad=360°2\pi\ \text{rad} = 360°, so 1 rad≈57.3°1\ \text{rad} \approx 57.3°.

Linear speed and angular velocity

In one revolution a body travels the circumference 2πr2\pi r in time TT:

v=2πrT=ωrv = \dfrac{2\pi r}{T} = \omega r

Points further from the centre move faster for the same ω: the outside of a turning wheel moves faster than the hub.

Why circular motion is accelerated

A body moving round a circle of radius r: its velocity points along the tangent while the centripetal force and acceleration point towards the centre O

Figure 1. Velocity is along the tangent; acceleration and force point to the centre. WASSCE Tutor diagram.

Velocity is a vector. Although the speed is constant, the direction of motion changes continuously, so the velocity changes. A changing velocity means an acceleration. This acceleration is directed towards the centre of the circle and is called centripetal ("centre-seeking") acceleration:

a=v2r=ω2ra = \dfrac{v^2}{r} = \omega^2 r

By Newton's second law, a resultant force must cause it. This centripetal force also acts towards the centre:

F=mv2r=mω2rF = \dfrac{mv^2}{r} = m\omega^2 r
Common mistake

Centripetal force is not a new kind of force. It is the name for whatever resultant force points to the centre: tension in a string, friction between tyres and road, gravity on a satellite, or the electric force on an electron in an atom. If that force disappears, the body moves off along the tangent in a straight line (Newton's first law), not outwards along the radius.

Worked examples

Worked example

1. A stone of mass 0.2 kg is whirled in a horizontal circle of radius 0.5 m at 3 revolutions per second. Find (a) the angular velocity, (b) the linear speed, (c) the tension in the string.

(a) ω=2πf=2π×3=18.85\omega = 2\pi f = 2\pi \times 3 = 18.85 rad s⁻¹.

(b) v=ωr=18.85×0.5=9.42v = \omega r = 18.85 \times 0.5 = 9.42 m s⁻¹.

(c) T=mω2r=0.2×18.852×0.5=35.5T = m\omega^2 r = 0.2 \times 18.85^2 \times 0.5 = 35.5 N.

Worked example

2. A car of mass 800 kg takes a bend of radius 50 m on a level road at 15 m s⁻¹. Find the friction force needed. If the maximum friction is 4000 N, what is the greatest safe speed?

F=mv2r=800×15250=3600 NF = \dfrac{mv^2}{r} = \dfrac{800 \times 15^2}{50} = 3600\ \text{N}
F=mv2r=800×15250=3600 N\begin{aligned}F &= \dfrac{mv^2}{r} \\ &= \dfrac{800 \times 15^2}{50} \\ &= 3600\ \text{N}\end{aligned}

Greatest speed: 4000=800v250⇒v2=250⇒v=15.84000 = \dfrac{800v^2}{50} \Rightarrow v^2 = 250 \Rightarrow v = 15.8 m s⁻¹.

Above this the tyres cannot supply enough centripetal force, and the car skids outwards along a tangent.

In Sierra Leone

A spin dryer or the spinning drum of a washing machine uses this idea: the drum wall pushes the clothes towards the centre, but the water passes through the holes, which supply no force. With nothing to keep it moving in a circle, the water flies off along tangents and leaves the clothes.

Applications

  • Vehicles on bends: friction provides the centripetal force; roads are banked to help.
  • Spin dryers and centrifuges: separate water from clothes, cream from milk, blood cells from plasma.
  • Satellites and the Moon: gravity provides the centripetal force.
  • Cyclists lean inwards when turning.
  • "Wall of death" riders and fairground rides.

Key points

  • Uniform circular motion: constant speed, changing velocity, so it is accelerated.
  • ω=2πT=2πf\omega = \dfrac{2\pi}{T} = 2\pi f, v=ωrv = \omega r.
  • Centripetal acceleration a=v2r=ω2ra = \dfrac{v^2}{r} = \omega^2 r, towards the centre.
  • Centripetal force F=mv2rF = \dfrac{mv^2}{r}, provided by tension, friction, gravity or another real force.
  • If the force stops, the body moves off along the tangent.

WASSCE examination focus

WAEC tests this

Expect to explain why a body moving in a circle at constant speed is accelerating, to define angular velocity and the radian, and to calculate centripetal force or tension for a stone on a string or a car on a bend. Objective items often ask for the direction of centripetal acceleration (towards the centre) or what happens when a string breaks (moves along the tangent).

Quick check

  1. In which direction does the centripetal acceleration act?
  2. A wheel makes 120 revolutions per minute. Find its angular velocity.
  3. What provides the centripetal force for a car turning on a flat road?

Answers: 1. Towards the centre of the circle. 2. f=2f = 2 Hz, ω=2π×2=12.6\omega = 2\pi \times 2 = 12.6 rad s⁻¹. 3. Friction between the tyres and the road.

Keep going with circular motion

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More lessons in Circular Motion

  1. Vertical circles, banked roads, gravitation and satellites🔒

All of Circular Motion →