WASSCE Mathematics · Indices

Indices: powers, bases and notation

By the WASSCE Tutor team

Updated 12 November 2026 · 14 min read · Prepared against the WASSCE syllabus.

When you write 232^3, you don't mean two times three. You mean two multiplied by itself three times: 2×2×2=82 \times 2 \times 2 = 8. The small 33 above the 22 is the index (plural: indices), and it tells you how many times to multiply the base by itself.

Indices are everywhere in mathematics — in algebra, in scientific notation, in compound interest, in geometric sequences. WAEC tests indices directly in every paper, both in objective and theory sections. Without solid foundations in this topic, indicial equations, logarithms, and surds will all feel impossible.

This lesson defines the basic terms, shows how to read and write powers, computes simple powers by hand, and introduces the special cases (010^1, 1n1^n, etc.) that will return throughout the topic.

Definition

In the expression ana^n:

  • aa is called the base — the number being multiplied.
  • nn is called the index (or exponent, or power) — the number of times the base appears in the product.
  • ana^n is read "aa to the power of nn" or "aa raised to the nn."

When nn is a positive whole number, ana^n means aa multiplied by itself nn times:

an=a×a×a×⋯×a⏟n timesa^n = \underbrace{a \times a \times a \times \cdots \times a}_{n \text{ times}}
an=a×a×a×⋯×a⏟n times\begin{aligned}a^n &= \underbrace{a \times a \times a \times \cdots \times a}_{n \text{ times}}\end{aligned}

Learning objectives

By the end of this lesson you should be able to:

  • read and write numbers in index form
  • identify the base and the index of a power
  • evaluate powers, including powers of negative numbers and fractions
  • recognise powers in patterns and sequences

Reading and writing powers

  • 232^3 = "two to the power of three" or "two cubed" = 2×2×2=82 \times 2 \times 2 = 8
  • 525^2 = "five squared" = 5×5=255 \times 5 = 25
  • 10410^4 = "ten to the fourth" = 10×10×10×10=10,00010 \times 10 \times 10 \times 10 = 10{,}000
  • 313^1 = "three to the power of one" = 33
  • 757^5 = "seven to the fifth" = 7×7×7×7×7=16,8077 \times 7 \times 7 \times 7 \times 7 = 16{,}807

The second-power case (a2a^2) is so common it has its own name: squared. The third-power case (a3a^3) is called cubed. From 444^4 onwards, just say "to the power of n".

Common powers to memorise

These come up so often in WAEC that knowing them by heart saves time.

Powers of 22:

PowerValue
212^122
222^244
232^388
242^41616
252^53232
262^66464
272^7128128
282^8256256
292^9512512
2102^{10}10241024

Powers of 33:

PowerValue
313^133
323^299
333^32727
343^48181
353^5243243
363^6729729

Powers of 55:

PowerValue
515^155
525^22525
535^3125125
545^4625625
555^531253125

Powers of 1010:

PowerValue
10110^11010
10210^2100100
10310^310001000
10410^410,00010{,}000
10510^5100,000100{,}000
10610^61,000,0001{,}000{,}000

Computing simple powers

For most WAEC questions, you compute powers by direct multiplication.

Example. Find 434^3.

43=4×4×4=16×4=644^3 = 4 \times 4 \times 4 = 16 \times 4 = 64.

Example. Find 545^4.

54=5×5×5×5=25×25=6255^4 = 5 \times 5 \times 5 \times 5 = 25 \times 25 = 625.

Example. Find 636^3.

63=6×6×6=36×6=2166^3 = 6 \times 6 \times 6 = 36 \times 6 = 216.

Step-by-step for larger powers

For 2102^{10}, multiply step by step:

21=22^1 = 2 22=42^2 = 4 23=82^3 = 8 24=162^4 = 16 25=322^5 = 32 26=642^6 = 64 27=1282^7 = 128 28=2562^8 = 256 29=5122^9 = 512 210=10242^{10} = 1024

For each step, just multiply the previous result by 22.

Worked example

Compute each.

(a) 34=3×3×3×3=9×9=813^4 = 3 \times 3 \times 3 \times 3 = 9 \times 9 = 81.

(b) 73=7×7×7=49×7=3437^3 = 7 \times 7 \times 7 = 49 \times 7 = 343.

(c) 27=1282^7 = 128 (memorised).

(d) 45=4×4×4×4×4=16×16×4=256×4=10244^5 = 4 \times 4 \times 4 \times 4 \times 4 = 16 \times 16 \times 4 = 256 \times 4 = 1024.

(e) 53=1255^3 = 125 (memorised).

(f) 112=11×11=12111^2 = 11 \times 11 = 121.

(g) 122=14412^2 = 144.

(h) 152=22515^2 = 225.

(i) 25×32=32×9=2882^5 \times 3^2 = 32 \times 9 = 288.

(j) 103×52=1000×25=25,00010^3 \times 5^2 = 1000 \times 25 = 25{,}000.

Negative bases — careful with signs

When the base is negative, the result depends on whether the exponent is even or odd.

Even exponent: result is positive.

  • (−2)2=(−2)×(−2)=4(-2)^2 = (-2) \times (-2) = 4 ✓
  • (−3)4=(−3)2×(−3)2=9×9=81(-3)^4 = (-3)^2 \times (-3)^2 = 9 \times 9 = 81 ✓
  • (−5)2=25(-5)^2 = 25 ✓

Odd exponent: result is negative.

  • (−2)3=(−2)×(−2)×(−2)=4×(−2)=−8(-2)^3 = (-2) \times (-2) \times (-2) = 4 \times (-2) = -8 ✓
  • (−3)3=−27(-3)^3 = -27 ✓
  • (−5)3=−125(-5)^3 = -125 ✓

The rule: in a product, count the number of negative factors. If even, the product is positive. If odd, the product is negative.

Sign convention — the minus sign before the base

There is a critical difference between −22-2^2 and (−2)2(-2)^2.

  • (−2)2=(−2)×(−2)=4(-2)^2 = (-2) \times (-2) = 4 — the parentheses tell you to square the negative number first.
  • −22=−(22)=−(4)=−4-2^2 = -(2^2) = -(4) = -4 — without parentheses, the minus is outside the exponent. You compute the power first, then apply the negative.

The convention: the exponent applies only to the immediately preceding number or grouping. A minus sign without parentheses is a separate operation applied after the power.

  • −32=−(3×3)=−9-3^2 = -(3 \times 3) = -9
  • (−3)2=(−3)×(−3)=9(-3)^2 = (-3) \times (-3) = 9
  • −24=−(16)=−16-2^4 = -(16) = -16
  • (−2)4=16(-2)^4 = 16

This is one of the most common WAEC traps. Read every minus carefully.

Worked example

Compute, watching the signs.

(a) (−3)2=9(-3)^2 = 9.

(b) −32=−9-3^2 = -9.

(c) (−2)4=16(-2)^4 = 16.

(d) −24=−16-2^4 = -16.

(e) (−4)3=−64(-4)^3 = -64.

(f) −43=−64-4^3 = -64. (Both forms agree here because 43=644^3 = 64 is positive, and applying minus gives −64-64.)

(g) (−1)100=1(-1)^{100} = 1 (even).

(h) (−1)101=−1(-1)^{101} = -1 (odd).

Bases that are fractions

When the base is a fraction, the index applies to the whole fraction.

(ab)n=anbn\left(\dfrac{a}{b}\right)^n = \dfrac{a^n}{b^n}
(ab)n=anbn\begin{aligned}&\left(\dfrac{a}{b}\right)^n \\ &= \dfrac{a^n}{b^n}\end{aligned}

Examples:

  • (12)3=1323=18\left(\dfrac{1}{2}\right)^3 = \dfrac{1^3}{2^3} = \dfrac{1}{8}
  • (23)2=49\left(\dfrac{2}{3}\right)^2 = \dfrac{4}{9}
  • (34)3=2764\left(\dfrac{3}{4}\right)^3 = \dfrac{27}{64}
  • (52)2=254\left(\dfrac{5}{2}\right)^2 = \dfrac{25}{4}

Notice how the value gets smaller when the fraction is less than 11, and larger when greater than 11.

Worked example

Compute each.

(a) (13)2=19\left(\dfrac{1}{3}\right)^2 = \dfrac{1}{9}.

(b) (25)3=8125\left(\dfrac{2}{5}\right)^3 = \dfrac{8}{125}.

(c) (32)4=8116\left(\dfrac{3}{2}\right)^4 = \dfrac{81}{16}.

(d) (110)3=11000\left(\dfrac{1}{10}\right)^3 = \dfrac{1}{1000}.

(e) (−12)3=−18\left(-\dfrac{1}{2}\right)^3 = -\dfrac{1}{8} (odd exponent → negative).

Bases of 00 and 11

Two special bases.

Base of 00

0n=00^n = 0 for any positive nn.

  • 01=00^1 = 0
  • 02=00^2 = 0
  • 05=00^5 = 0

Note: 000^0 is a special case — sometimes defined as 11, sometimes undefined. WAEC does not typically test this corner case.

Base of 11

1n=11^n = 1 for any nn.

  • 11=11^1 = 1
  • 12=11^2 = 1
  • 1100=11^{100} = 1
  • 1−5=11^{-5} = 1

If you ever see 11 to a power, the answer is 11 — no matter the exponent.

Why indices matter

Indices appear everywhere:

Scientific notation

  • 34,000=3.4×10434{,}000 = 3.4 \times 10^4
  • 0.0056=5.6×10−30.0056 = 5.6 \times 10^{-3}

Areas and volumes

  • Area of a square with side ss: s2s^2
  • Volume of a cube with side ss: s3s^3
  • Volume of a sphere: 43πr3\dfrac{4}{3}\pi r^3

Growth and decay

  • Population after tt years: P0×rtP_0 \times r^t (where rr is the growth rate)
  • Compound interest: P(1+r)nP(1 + r)^n

Geometric sequences

  • 1,2,4,8,16,32,…1, 2, 4, 8, 16, 32, \ldots — each term is the previous one times 22. The nn-th term is 2n−12^{n-1}.
  • 1,3,9,27,81,…1, 3, 9, 27, 81, \ldots — nn-th term is 3n−13^{n-1}.

Later topics (sequences, financial arithmetic, variation) all rely on a solid understanding of indices.

Comparing values raised to powers

Which is bigger, 343^4 or 434^3? Don't guess — compute.

34=813^4 = 81. 43=644^3 = 64. So 34>433^4 > 4^3.

Which is bigger, 2102^{10} or 10210^2? 210=10242^{10} = 1024, 102=10010^2 = 100. So 210≫1022^{10} \gg 10^2.

Which is bigger, 123\dfrac{1}{2^3} or 132\dfrac{1}{3^2}? Compute: 18\dfrac{1}{8} vs 19\dfrac{1}{9}. Since 18>19\dfrac{1}{8} > \dfrac{1}{9}, the first is bigger.

Worked example

Compare each pair.

(a) 535^3 vs 353^5. 53=1255^3 = 125. 35=2433^5 = 243. So 53<355^3 < 3^5.

(b) 424^2 vs 242^4. 42=164^2 = 16, 24=162^4 = 16. Equal.

(c) 626^2 vs 262^6. 62=366^2 = 36, 26=642^6 = 64. So 62<266^2 < 2^6.

(d) (12)3\left(\dfrac{1}{2}\right)^3 vs (13)2\left(\dfrac{1}{3}\right)^2. First: 18\dfrac{1}{8}. Second: 19\dfrac{1}{9}. So 18>19\dfrac{1}{8} > \dfrac{1}{9}.

In Sierra Leone

A mosquito population in a stagnant pond in Bo doubles every day. On day 11, there are 5050 mosquitoes. By day 1010, the population is 50×29=50×512=25,60050 \times 2^9 = 50 \times 512 = 25{,}600. By day 2020, it is 50×21950 \times 2^{19}, which is a much bigger number.

Indices capture this exponential growth precisely. Each day's population is the previous day's population times 22 — the same operation repeated. Without indices, we'd have to multiply by 22 ten times explicitly. With indices, 292^9 does it in one symbol.

Common mistake

Common errors with simple powers:

1. Multiplying instead of using powers.

  • 23≠62^3 \neq 6. 2×3=62 \times 3 = 6 is multiplication. 23=82^3 = 8 is the power.

2. Sign error with negative bases.

  • (−3)2=9(-3)^2 = 9 (square cancels the negative).
  • −32=−9-3^2 = -9 (the minus is outside, applied after).

3. Forgetting the parentheses.

  • −24≠(−2)4-2^4 \neq (-2)^4. The first is −16-16. The second is 1616.

4. Wrong order with fractions.

  • (23)3=827\left(\dfrac{2}{3}\right)^3 = \dfrac{8}{27}, NOT 227\dfrac{2}{27}.

5. Confusing ana^n with a×na \times n.

  • 53=1255^3 = 125. 5×3=155 \times 3 = 15. Very different.

6. Adding indices instead of multiplying base.

  • 23+23=8+8=162^3 + 2^3 = 8 + 8 = 16, NOT 26=642^6 = 64. The rule for adding same powers of the same base is different from multiplying them (see the laws in the next lesson).

WASSCE examination focus

WAEC tests this

Foundational power questions in WAEC:

  • Compute a power. Find the value of 343^4. (Answer: 8181)
  • Compute with negative base. Find the value of (−2)3(-2)^3. (Answer: −8-8)
  • Distinguish sign cases. Find the value of −52-5^2 vs (−5)2(-5)^2. (−25-25 vs 2525)
  • Compare powers. Which is greater: 535^3 or 353^5?
  • Power of a fraction. Find (23)3\left(\dfrac{2}{3}\right)^3.

The key foundational skill is the sign convention and the memorisation of common powers. These build the platform for everything that follows.

Practice problems

1. Compute 434^3.

2. Compute 727^2.

3. Compute 282^8.

4. Compute (−3)4(-3)^4.

5. Compute −34-3^4.

6. Compute (14)2\left(\dfrac{1}{4}\right)^2.

7. Compute (25)3\left(\dfrac{2}{5}\right)^3.

8. Find the value of 25−322^5 - 3^2.

9. Find the value of 53+435^3 + 4^3.

10. Find (−1)15+(−1)20(-1)^{15} + (-1)^{20}.

11. A square has side 1212 cm. What is its area?

12. A cube has side 55 cm. What is its volume?

Worked solutions

1. 43=4×4×4=16×4=644^3 = 4 \times 4 \times 4 = 16 \times 4 = 64.

2. 72=497^2 = 49.

3. 28=2562^8 = 256.

4. (−3)4=81(-3)^4 = 81 (even exponent → positive).

5. −34=−(81)=−81-3^4 = -(81) = -81 (minus outside, applied after the power).

6. (14)2=116\left(\dfrac{1}{4}\right)^2 = \dfrac{1}{16}.

7. (25)3=8125\left(\dfrac{2}{5}\right)^3 = \dfrac{8}{125}.

8. 25−32=32−9=232^5 - 3^2 = 32 - 9 = 23.

9. 53+43=125+64=1895^3 + 4^3 = 125 + 64 = 189.

10. (−1)15=−1(-1)^{15} = -1 (odd). (−1)20=1(-1)^{20} = 1 (even). Sum: −1+1=0-1 + 1 = 0.

11. Area = 122=14412^2 = 144 cm².

12. Volume = 53=1255^3 = 125 cm³.

What's next

In the next lesson we cover the laws of indices — the rules that let you combine, simplify, and manipulate expressions with powers. am×an=am+na^m \times a^n = a^{m+n}. aman=am−n\dfrac{a^m}{a^n} = a^{m-n}. (am)n=amn(a^m)^n = a^{mn}. (ab)n=anbn(ab)^n = a^n b^n. These laws, with zero, negative and fractional indices and indicial equations, underlie nearly every indices question on WAEC.

Keep going with indices

This is one of 6 lessons in Indices. Start free with the first lesson of every topic, then unlock them all, plus exam-style practice marked instantly and guided learning tools, from 25 NLe.

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More lessons in Indices

  1. Laws of indices and indicial equations🔒
  2. The Laws of Indices🔒
  3. Negative and Zero Indices🔒
  4. Fractional Indices🔒
  5. Solving Indicial Equations and the WAEC Trap🔒

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